So, after three posts of

we have arrived at MANOVA.  If you skipped those three posts, feel shame at trying to take shortcuts, go back and read them.

Before we dive into coding, let’s take a look at some basic background on MANOVA.

The difference between ANOVA and MANOVA is simple

  • With ANOVA you have one dependent variable
    With MANOVA you have multiple dependent variables

How does that work? Think back to what you know about multiple correlation

In correlation, you are looking at the relationship between two variables, X and Y. You predict changes in X from changes in Y

Y = bX

In multiple correlation you are looking at the relationship between Y and MULTIPLE X variables.

You have an equation something like

Predicted Y = b0X0 + b1X1 + b2X2 + b3X3

And you are looking at how the Y variable changes in relation to the PREDICTED Y. Notice that predicted Y is a sum of all of your variables, each of which is multiplied by a regression coefficient.

The correlation between these predicted Ys and the actual Y is your multiple R and the multiple R-squared in ANOVA or regression is the square of the multiple R.

The multiple R-squared answers the question – how much of the variance in the dependent variable can be explained by variance in the independent variable (s) ?

In the case of ANOVA, this variance is in group membership, so we are testing the null hypothesis that the mean of group1 = the mean of group 2 all the way to group N

With MANOVA, you have multiple variables on the Y side of the equation

The variable you are predicting/ explaining in this case is also a weighted sum

Dependent = w1Y1 + w2Y2 + w3Y3

Our null hypothesis is that the mean of this weighted combination is equal for groups 1, 2 and all the way up to group N

Instead of looking at a multiple R-squared in this case, we look at two other statistics, Wilk’s lambda and Pillai’s trace

  • Assumptions of MANOVA
  • Independent, randomly sampled observations
  • Variables follow a multivariate normal distribution
  • Homoscedasticity – population covariances for the dependent groups are equal
  • Relationship of dependent variables is linear (because notice you made the dependent into a linear equation)

Also note that in the case of a repeated measures ANOVA certainly assumption 1 and possibly assumption 3 are violated

When you have conducted your MANOVA the first thing you should look at is the Multivariate tests – Wilk’s lambda, Pillai’s trace . Rejecting the null hypothesis that the model does not explain the difference in the VECTOR of means then leads you to examine the second logical question, which of these dependent variables differs ? So , if you don’ t have a significant, lambda, trace, etc. STOP. If you do, move on and check out the univariate F-tests. If your F is significant, go on to post hoc tests.

ETA-squared is the variance accounted for IN THE LINEAR COMBINATION OF THE DEPENDENT VARIABLES by the model.

Mertler and Vannata said it well.

“When the IV has only two categories, the F test for Pillai’s Trace, Wilks’ Lambda, and Hotelling’s Trace will be identical. When the IV has three or more categories, the F test for these three statistics will differ slightly but will maintain consistent significance or nonsignificance. Although these test statistics may vary only slightly, Wilks’ Lambda is the most commonly reported MANOVA statistic. Pillai’s Trace is used when homogeneity of variance-covariance is in question. If two or more IVs are included in the analysis, factor interaction must be evaluated before main effects. “

 

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Julia yellingWhere is the Multivariate Analysis of Variance ?

You promised there would be MANOVA ! Now we’re in the third post!

First there was recoding of variables.

Then, there was creating scales. 

Now, we’re looking at reliability.

Patience is a virtue.

Before we get to doing a MANOVA we want to be sure that our dependent and independent variables are reliable and valid. Let’s move on to reliability.

I’m going to do a correlation matrix and a Cronbach alpha, which is a measure of internal consistency. The rationale is that if items all measure the same construct – say, knowledge of health practices, or autonomy or acceptance of wife beating – then those items should be related to one another. An alpha of 0 would indicate the covariance of items in the scale are zero, so, your scale sucks. An alpha of .95 would mean your scale is amazingly consistent.

So, I did three analysis for my three scales

Title "Health Variables " ;
proc corr data=example alpha ;
var hbs1 hbs3-hbs7 ;

Title "Wife beating variables" ;
proc corr data=example alpha ;
var GR34 - GR39 ;

Title "Decision Variables" ;
proc corr data=example alpha ;
VAR D_GR1A GR2A D_GR3A D_GR4A GR5a GR6A D_GR7A GR8A
D_GR9A GR9F D_GR10A D_GR12A GR10F GR12F ;

Let’s skip the simple statistics, mean, etc. you get from these analyses and go to the alpha

Screen Shot 2017-06-14 at 9.48.47 PM

The alpha for the health scale is pretty bad. The value for the raw scores is .31, for standardized items, still really bad at .32.  When we look at how deleting a variable would improve the alpha, if we dropped the first variable , the alpha would go up to .34 – but that is still awful.

For the wife-beating scale the raw value for alpha was .81 and also for the standardized value. So, that one was pretty good as far as reliability.

I put all of the decision variables together, the ones on whether the woman was involved in making decisions, could go places on her own, needed to ask permission to go places. The Cronbach alpha for the raw variables was .65, for standardized variables .81. Note that standardized variables are placed on the same metric, so my idea of some variables being much more important than others did not pan out.

So … I standardized the variables, then I read in that data set and created two scales, one that was a sum of the decision  variables and the other that was the mean of the 6 wife-beating variables. There was no particular reason for using the mean of the six variables as opposed to just adding them up. I did both methods to show it was an option.

BEWARE THE SUM FUNCTION – Note, I did not use the sum function. If you add up the values, as shown below, and one of the variables has a missing value then the value of the sum is going to be missing. If you used the SUM function, the variables that have non-missing values would be added up, so the missing value would be treated as a zero. There are times where that is acceptable. This is not one of those times.

While I’m at it, I want to check whether the scales have approximately normal distributions. A perfectly normal distribution would have skewness and kurtosis values of 0.

proc standard data=example mean=0 std=1 out=MAN_data;

Data create_manova ;
set man_data ;
* I could have used the mean function here, but I didn't ;
decision = D_GR1A + GR2A + D_GR3A + D_GR4A + GR5a + GR6A + D_GR7A + GR8A +
D_GR9A + GR9F + D_GR10A + D_GR12A + GR10F + GR12F ;
beating = mean(of gr34-gr39);

proc univariate data=create_manova ;
var decision beating ;

The skewness values were relatively low: -1.3 and 0.2 for the two scales and kurtosis values were 2.0 and -1.2  . Since my scales aren’t a radical departure from normality, I’m now going on to MANOVA – finally!

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Last time, we saw how to recode variables to score answers correct or incorrect, on a rating scale and weighted by importance. Today, we’re going to look at creating some scales from those variables because for reasons I’m sure I have written about at some point in the past, single items are usually not very reliable. Whether you use SAS, SPSS, R or any other statistical package, you are still going  to need to follow the steps of recoding your variables and creating and validating your scales before you get into MANOVA. Or, at least, you will if you are smart.

First, I want to check that there are no obvious errors or other problems in my data.
PROC MEANS DATA=example ;
VAR gr2A -- gr39 hbs1 --d_gr12a ;

You could type in the variable names but that is a lot of typing. The double dashes mean to include all variables in the data set in order from the first variable to the one that comes after the dashes. How do you know what order the variables are in? Click on the OUTPUT DATA tab at the top and look to the left under COLUMNS.

output da

If you didn’t just run a program creating your data and hence don’t have an OUTPUT DATA tab, you can find your data file by clicking the MY LIBRARIES tab and then clicking on the library (directory) where your data are kept and clicking on the dataset to open it. You can also use the PROC CONTENTS procedure but today we are being all pointy and clicky with SAS Studio.

Sometimes you will see something like:

VAR item1 – item12 ;

The single dash is used for variables that end in a number and if you don’t have item1, item2 all the way through item12, it will give you an error and not run. Then you will be sad.

PROC MEANS will give you the N, mean, standard deviation, minimum and maximum.

Here are a few things to consider.

  • Is the N substantially less than you had expected? If so, you have a lot of missing data and you should investigate that. The lowest N I have is 37, 814 out of 39, 430 people so not bad, but I might want to look at that one item, since most of the items have close to 39,000 for an N
  • Is your standard deviation zero? STOP RIGHT THERE!  On just what variable could 39,000 people give the same response? This likely shows a big problem with your data. I did not have that problem, so I continued.
  • Are your minimum and maximum the minimum and maximum possible scores for the item? Now, this may not always be the case. On a scale of 1 to 10, say, with a sample of 50 people, maybe no one will say 1. However, I have over 39,000 people and the items are 0 or 1, o – 2  or 1- 3, so I should have people from the minimum to the maximum or something is wrong. Nothing is wrong, and I continue.
  • Are the means about what you expect? Well, I’m not really an expert on social structure and family relations in India, so I can’t say. About a third of the women said it was usual for a husband to beat his wife if her dowry was not what was expected. About three-fourths said they would be allowed to visit a family or friend’s home alone.

Okay, so my results from the means procedure looks okay. Now what?

Next, I’m going to do a factor analysis to see if my supposition is supported of three scales related to health, beating your wife and autonomy.

Here is the code for my factor analysis.

PROC FACTOR DATA =example SCREE ROTARE= VARIMAX NFACTORS=5;
VAR gr2A -- gr39 hbs1 --d_gr12a ;

This is actually the second one I ran. In inspecting the results for the first, between the eigenvalues and scree plot, I decided that at most I should retain five factors. I’ve written a lot about factor analysis on this blog previously, so I’m not going to go into detail here.  In short, the decision-making variables mostly loaded on the first factor with factor loadings of .70 and higher. The median communality estimate for those items was about .67.  In short, considerable evidence for a decision-making factor. The wife-beating variables loaded on the second factor. All but one loaded above .67, and even that variable (Beating your wife if she had an extramarital affair – which 84% of the women said was accepted in their communities) loaded at .40. The variables regarding needing permission to go places loaded on the third factor and also had high communality estimates. The variables regarding going places by yourself loaded on the fourth factor and also had high communality estimates.

The health variables were a different story. Four out of six loaded between .47 and .67 on the fifth factor. The other two did not load on any factor.

It is starting to look like at this point that it is okay to retain the wife-beating items as a scale. The various measures of autonomy  – decision-making, going places on your own and needing permission – seem to hang together within factors. I think it would be reasonable to put all three of these together in one scale. I talked about parceling in the past, and I could have done that as a step here, and then re-run the factor analysis to support (or not) my supposed autonomy factor. Since I have limited time and simply doing this analysis for educational and illustrative purposes, I skipped over this to the next procedure, which is reliability analysis.

Since this post is pretty long already, I’ll save that for the next post.

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Other people want to go see the new Wonder Woman movie. I’ve been wanting to talk about MANOVA, but first, we need some decent dependent and independent measures.

I have the India Human Development Survey data on over 39,000 women and my hypothesis is that education is related to women’s rights’ issues, especially autonomy, health practices knowledge and domestic violence. I also think that mobility might be related, as women who get out of their native village might be exposed to new ideas.

Before I can test out my (supposedly) brilliant hypotheses, I need to create some variables because it turns out when they were collecting data in India in 2011 they were not thinking about my convenience. (Yes, I, too, am appalled by this lack of consideration.)

Independent Variables

First, I will need to create my independent variables from

EW11 Differences in family by mobility

1= same village/ town

2= another village

3 = another town

4 = metro (since only 1% fall in here, I’m going to delete this category)

and education (see below)

Items that will go into dependent variables (maybe)

HEALTH QUESTIONS

HB1 Milk harmful

HB3. 1st milk good for baby 

Hb4 chulha smoke good

Hb5 child diarrhea drink more

Hb6 illness spread through water

Hb7 malaria spread

DECISIONS

The items below are scored 1 if the respondent decides, 0 if the respondent does not decide. (More than 1 person can decide, so if both husband and wife decide, the answer will be 1 for both. In this case, I just looked at if the wife had a say in the decision.)

  • GR1a Cooking
  • GR2A Expensive purchases.      
  • GR3A Decides number of children
  • GR4A Decides what to do if sick
  • GR5A Decides whether to buy land  
  • GR6A Decides wedding expense
  • GR7A Decides if child is sick
  • GR8A Decides who your children should marry

The items below are score 1 if the woman is allowed to do these things alone and 0 if she is not.

  • GR9F Can visit health center alone
  • GR10F Can visit relative/ friend alone
  • GR12F. Can go short distance alone

These items relate to whether the woman needs to ask permission for activities, with  0 = no, 1 = must inform someone and 2 = yes

  • GR9A Ask permission to visit health center
  • GR10A Ask permission to visit relative
  • GR12A. Ask permission to travel by bus/train

 

WIFE BEATING QUESTIONS

GR34 – GR39  – All of these relate to under what circumstances it is acceptable, coded yes = 1 or 0 = no.

As you can see, well, I hope you can see, each of these presents a different date re-coding problem.

  • Mobility and education needs to be coded into categories (there is a minor reason I will explain in a later post why this is not necessary but convenient), with the fourth category deleted,
  • Health questions need to be scored as correct or incorrect.
  • Decision questions are all scored equally – so deciding what food  to cook and how many children you have are each scored a 1. I think that’s not right and I want to weight some decisions more than others.
  • Independence questions need to be reverse coded, so not asking permission is a 2 and asking permission is a 0
  • Wife-beating questions need no recoding

So … here we go. The first thing we’re going to do is create categories. Notice I don’t do anything with the category 4 for mobility, so those people will just have a missing value for MOBILITY and be dropped from the analysis.

Also, a note on ELSE as opposed to just IF statements.

I could just use all IF statements but that would be inefficient. It doesn’t really matter here with 39,000 records but if I had millions it would slow down processing. The ELSE statement is only processed if the preceding IF statement is false.

NOTE!!!  In the second set of IF- ELSE statements, I have

else if ew8 < 9 and ew8 ne . then education = “ELEM”;

This statement is only executed IF the preceding IF statement was false.  Without the ELSE, everything less than 9, including those who had 0 years of education, would be set to ELEM.  Without the and ew8 ne .  in this statement, anyone that had missing data would be set to ELEM along with anyone who had 1-8 years of education.


data example ;
set mydata.india ;
If EW11 = 1  then Mobility = “None” ;
else if EW11 = 2 then mobility = “Vill” ;
else if EW11 = 3 then mobility = “TOWN”;

if ew8 = 0 then education = “NONE” ;
else if ew8 < 9 and ew8 ne . then education = “ELEM”;
else if ew8 > 8 then education = “HS +”;

*** The statements below recode the health items ;

*** For hb1 the correct answer is 0, so  1-hb1   will score respondents who said 0 as correct (= 1) and those who said 1 as incorrect (=0);

*** For hb3 the correct answer is 1, so respondents who said 1 are scored as correct (= 1) and those who said any number higher than 1 as incorrect (=0);

*** For hb4 – hb7, the correct answer is scored as correct (=1) and any numbers in the incorrect set scored as incorrect (=0);
*** HEALTH QUESTIONS ;
hbs1 = 1- hb1 ;

If hb3 = 1 then hbs3 = 1 ;
Else if hb3 > 1 then hbs3 = 0 ;
If hb4 = 2 then hbs4 = 1 ;
Else if hb4 in (1,3) then hbs4 = 0 ;
If hb5 = 2 then hbs5 = 1 ;
Else if hb5 in (1,3,4) then hbs5 = 0 ;
If hb6 = 2 then hbs6 = 1 ;
Else if hb6 in (1,3,4) then hbs6 = 0 ;

If hb7 = 3 then hbs7 = 1 ;
Else if hb7 in (1,2,4) then hbs7 = 0 ;

 

/* DECISION QUESTIONS */
/* ALSO INCLUDES ADDITIONAL ITEMS NOT RECODED */

**** Here, I multiplied items by a factor based on my estimation of importance ;
D_GR1A = GR1A* 0.5 ;
D_GR3A = GR3A * 10 ; * BECAUSE I THINK IT’S IMPORTANT ;
D_GR4A = GR4A *2 ;
D_GR7A = GR7A *2 ;

**** These items are subtracted from 3 so doesn’t have to tell anyone = 2 ;

****  Needs to inform someone = 1 and needs to ask permission = 0 ;
D_GR9A = 3 – GR9A ;
D_GR10A = 3 – GR10A ;
D_GR12A = 3 – GR12A ;

**** KEEPS THE VARIABLES I PLAN TO USE ;
Keep EW8 EW5  Ew6 EW10  EW14a   EW12a EW12b
HBS1 HBs3-HBS7 D_GR1A GR2A D_GR3A D_GR4A GR5a GR6A D_GR7A GR8A
D_GR9A GR9F D_GR10A D_GR12A GR10F GR12F GR34 – GR39 mobility education;

So, there we go. You might think I would dive into a Multivariate Analysis of Variance now but you would be wrong. The next thing I am going to do is check the validity of my scales through a combination of factor analysis, univariate statistics and reliability analysis. Only after  that step will I do the MANOVA.

I’m teaching a course on multivariate statistics and for some of the students it’s been a minute since their last inferential statistics course.

So, I have been doing a few videos here and there to refresh, for example, what is a repeated measures ANOVA and why you might want to do it.

 

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Since I had done a few youtube videos on using SAS Studio, I thought I would add them to my blog. This one uses the characterize data task to take a quick look at the data, but I suppose you could have guessed that from the title.

 

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Hopefully, you have read my Beginner’s Guide to Propensity Score matching or through some other means become aware of what the hell propensity score matching is. Okay, fine, how do you get those propensity scores?

Think about this carefully for a moment, if you are using quintiles, you are matching people by which group they fit into as far as probability of being in the treatment group. So, if your friend, Bob, has a predicted probability of 15% of being in the treatment group, his quintile would be 1, because he is in the lowest 20%, that is, the bottom fifth, or quintile. If your other friend, Luella, has a predicted probability of being in the treatment group of 57%, then she is in the third quintile.

Oh, if only there were a means of getting the predicted probability of being in a certain category – oh, wait, there is!

Let’s do binary logistic regression with SAS Studio

First, log into your SAS Studio account.

Second, you probably need to run a program with a LIBNAME statement to make your data available. I am going to skip that step because in this example I’m going to use one of the SASHELP data sets and create a data set in mu WORK library as so, so I don’t need a LIBNAME for that but, as you will see, I do need it later. Here is the program I ran.

data psm_ex ;
set sashelp.heart ;
if smoking = 0 then smoker = 0 ;
else if smoking > 0 then smoker = 1;
WHERE weight_status ne “Underweight” ;

libname mydata “/courses/blahblah/c_123/” ;

run;

My question is if I had people who had the same propensity to smoke, based on age, gender, etc. would smoking still be a factor in the outcome (in this case, death). To answer that, I need propensity scores.

Third, in the window on the left, click on TASKS AND UTILITIES, then STATISTICS and select BINARY LOGISTIC REGRESSION, as shown below.

1select_task

Next,  choose the data set you want by clicking on the thing under the word DATA that looks like a table of data and selecting the library and data set in that library. Next, under RESPONSE, click the + sign and select the dependent variable for which you want to predict the probability. In this case, it’s whether the person is a smoker or not. Click the arrow next to EVENT OF INTEREST and pick which you want to predict, in this case, your choices are 0 or 1. I selected 1 because I want to predict if the person is  a smoker.

Below that, select your classification variable,

choosing data

 

There is also a choice for continuous variables (not shown) on the same screen.  I selected AGEATSTART.

I’m going to select the defaults for everything but OUTPUT. Click the arrow at the top of the screen next to MODEL and keep clicking until you see the OUTPUT tab. Click on the box next to CREATE OUTPUT DATASET. Browse for a directory where you want to save it.  I had set that directory in my LIBNAME statement (remember the LIBNAME statement) so it would be available to save the data. Select that directory and give the data set a name.

Click the arrow next to PREDICTED VALUES and in the 3 boxes that appear below it, click the box next to predicted values.

create output data set

 

After this, you are ready to run your analysis. Click the image of the little running guy above.  When your analysis runs you will have a data set with all of your original data plus your predicted scores.

predicted

 

Now, we just need to compute quintiles.You could find the quintiles by doing doing this:

PROC FREQ DATA=MYDATA.STATSPSM ;

tables pred_ ;

and look for the 20th, 40th, etc. percentile

However, an easier way if you have thousands of records is

proc univariate data=mydata.statspsm ;
var pred_ ;
output pctlpre=P_ pctlpts= 20 to 80 by 20;
proc print data=data1 ;

Which will give you the percentiles.

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One advantage of writing this blog for almost a decade is that there are a lots of topics I have already covered. However, software moving at the speed that it does, there are always updates.

So, today I’m going to recycle a couple of older posts that introduce you to propensity score matching. Then, tomorrow, I will show you how to get your propensity scores with just pointing and clicking with a FREE (as in free beer) version of SAS.

beer

Before you even THINK about doing propensity score matching …

Propensity score matching has had a huge rise in popularity over the past few years. That isn’t a terrible thing, but in my not so humble opinion, many people are jumping on the bandwagon without thinking through if this is what they really need to do.

The idea is quite simple – you have two groups which are non-equivalent, say, people who attend a support group to quit being douchebags and people who don’t. At the end of the group term, you want to test for a decline in douchebaggery.

However, you believe that that people who don’t attend the groups are likely different from those who do in the first place, bigger douchebags, younger, and, it goes without saying, more likely to be male.

The very, very important key phrase in that sentence is YOU BELIEVE.

Before you ever do a propensity score matching program you should test that belief and see if your groups really ARE different. If not, you can stop right now. You’d think doing a few ANOVAs, t-tests or cross-tabs in advance would be common sense. Let me tell you something, common sense suffers from false advertising. It’s not common at all.

Even if there are differences between the groups, it may not matter unless it is related to your dependent variable, in this case, the Unreliable Measure of Douchebaggedness.

For more information, you can read the whole post here, also read the comments because they make some good points

What type of Propensity Score Matching is for you? A statistics fable

Once upon a time there were statisticians who thought the answer to everything was to be as precise, correct and “bleeding edge” as possible. If their analyses were precise to 12 decimal places instead of 5, of course they were better because as everyone knows , 12 is more than 5 (and statisticians knew it better, being better at math than most people).

Occasionally, people came along who suggested that newer was not always better, that perhaps sentences with the word “bleeding” in them were not always reflective of best practices, as in,

“I stuck my hand in the piranha tank and now I am bleeding.”

Such people had their American Statistical Association membership cards torn up by a pack of wolves and were banished to the dungeon where they were forced to memorize regular expressions in Perl until their heads exploded. Either that, or they were eaten by piranhas.

Perhaps I am exaggerating a tad bit, but it is true that there has been an over-emphasis on whatever is the shiniest, new technique on the block. Before my time, factor analysis was the answer to everything. I remember when Structural Equation Modeling was the answer to everything (yes, I am old). After that, Item Response Theory (IRT) was the answer to everything. Multiple imputation and mixed models both had their brief flings at being the answer to everything. Now it is propensity scores.

A study by Sturmer et al. (2006) is just one example of a few recent analyses that have shown an almost logarithmic growth in the popularity of propensity score matching from a handful of studies to in the late nineties to everybody and their brother.

You can read the rest of the post about choosing a method of propensity score matching here. If your clicking finger is tired, the take away message is this —  quintiles, which are much simpler, faster to compute and easier to explain, are generally just as effective as more complex methods.

Now that we are all excited about quintiles, the next couple of posts will show you how to compute those in a mostly pointy-clicky manner.

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I have to choose between either SAS or SPSS for a new course in multivariate statistics. You can take it up with the university if you like, but  these are my only two options, in part because the course is starting soon.

I need to decide in a few days which way to go. Here are my very idiosyncratic reasons for one versus the other:

  • SPSS
  • There is a really good textbook on multivariate statistics that I think would be perfect for these students and it uses SPSS. The book is Advanced and Multivariate Statistics by Mertler & Vannatta, in case you were wondering.
  • SPSS can be installed pretty easily on the desktop and these are pretty non-technical students, so that’s a plus.
  • The point and click interface for SPSS is pretty easy and similar to Excel which most people have used.
  • Personally, I haven’t used SPSS in a while so it would be nice to use something different.

SAS

  • Students can just register and go to the website to use SAS Studio
  • Structural equation modeling and other advanced statistics procedures built in and not on add-on
  • SAS Studio is free vs $80 or so for students and $260 for professor (i.e., me) to buy SPSS academic versions including add-ons needed
  • I’m more familiar with SAS and find it easier to code than SPSS syntax.

I’ve toyed with the idea of showing both options but that uses up class time better spent on teaching, for example, how do you interpret a factor loading or AIC.

My big objection to SAS is I can’t find a recent textbook that is good for a multivariate analysis course that is in a social sciences department. The best one is by Cody and that is from 2005. I also use a couple of chapters from the Hosmer & Lemeshow book on Applied Logistic Regression , but I need something that covers factor analysis, repeated measures ANOVA and hopefully, MANOVA and discriminant function analysis, too.

I think most of these students have careers in non-profits and they are not going to be creating new APIs to analyze tweets or anything using enormous databases, so the ability to analyze terabytes is moot. This will probably be their second course in statistics and maybe their first introduction to statistical software.

Suggestions are more than welcome.

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P. S. You can skip the hateful comments on why SAS and SPSS both suck and I should be using R, Python or whatever your favorite thing is. Universities don’t usually give carte blanche. These are my two choices.

P.P.S. You can also skip the snarky comments on how doctoral students should have a lot more statistics courses, all take at least a year of Calculus, etc. Even if I might agree with you, they don’t and I need tools that work for the students in my classes, not some hypothetical ideal student.

It ought to be easier than this and perhaps I could have found an easier way if I had more patience than the average ant or very young infant. However, I don’t.
Here was the problem. I wanted control charts for two different variables, satisfaction with care, surveyed at discharge, and satisfaction with care 3 months after discharge.
The data was given in the form of the number of patients out of a sample of 500 who reported being unsatisfied. PROC SHEWHART does not have a WEIGHT statement. You could try using the WEIGHT statement in PROC MEANS but that won’t work. It will give you the correct means if you have the number unsatisfied (undisc = 1)  and the number satisfied (undisc =0) out of 500, but the incorrect standard deviation because the N will be 2, according to SAS.
So, here is what I did and it was not elegant but it did work.
  1. I created two data sets, named q4disc and q4disc3, keeping the month of discharge and the number dissatisfied at discharge and dissatisfied 3 months later, respectively.
  2. I read in the 3 values I was given, month of sample, number unsatisfied at discharge and number unsatisfied 3 months later.
  3. Now, I am going to create a data set of raw data based on the numbers I have. First, in a do loop, for as many as people said they were unsatisfied, I set the value of undisc (unsatisfied at discharge) to to 1 and output a record to the q4disc dataset.
  4. Next, in a do loop for 500- the number dissatisfied, I set undisc = 0 and output a record to the same dataset.
  5. Now, repeat steps 3 & 4 to create a data set of the values of people unhappy 3 months after discharge.
  6. Following the programming statements are the original data.

So, now, I have created two data sets of 6,000 records each with three variables. Doesn’t seem that efficient of a way to do it but now I have the data I need and it didn’t take long and doesn’t take up much space.

data q4disc (keep = undisc month) q4disc3 (keep = undisc3 month) ;
input month $ discunwt disc3unwt ;
Do I = 1 to discunwt ;
    undisc = 1 ;
    output q4disc ;
end ;
Do J = 1 to (500-discunwt) ;
   undisc = 0 ;
   output q4disc;
end ;
Do k = 1 to disc3unwt ;
   undisc3 = 0 ;
   output q4disc3 ;
End ;
Do x = 1 to (500 -disc3unwt) ;
  undisc3 = 1 ;
   output q4disc3;
end;
datalines ;
JAN 24 17
FEB 44 24
MAR 36 15
APR 18 8
MAY 16 11
JUN 19 7
JUL 17 11
AUG 18 9
SEP 27 10
OCT 26 15
NOV 29 12
DEC 26 11
;
RUN ;
proc shewhart data=WORK.Q4disc;
xschart undisc * month /;
run;
According to SAS

“The XSCHART statement creates and charts for subgroup means and standard deviations, which are used to analyze the central tendency and variability of a process.”

For the three months after discharge variable, just do another PROC SHEWHART with q4disc3 as the dataset and undisc3 as the measurement variable.

OR , once you have the dataset created, you can get the chart using SAS Studio by selecting the CONTROL CHARTS task

Control charts window with month as subgroup and undisc as measure

Either way will give you this result:

Control chart

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